#### Answer

This is true.

#### Work Step by Step

Let the integers be $b$ and $b+1$. Expanding, we find that their squares are (respectively) $b^2$ and $b^2+2b+1$. Subtracting, we get $2b+1$, which is (by definition) odd, so the statement is true.

Published by
Cengage Learning

ISBN 10:
0-49539-132-8

ISBN 13:
978-0-49539-132-6

This is true.

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