## Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning

# Chapter 2 - The Logic of Compound Statements - Exercise Set 2.3: 24

#### Answer

The argument is true by Elimination

#### Work Step by Step

Let p be the statement that This real number is rational. Let q be the statement that This real number is irrational. This real number is rational or it is irrational (p ∨ q) This real number is not rational (¬p) ∴ This real number is irrational (q) So the argument form is: p ∨ q ¬p ∴ q Which is true by the rule of inference known as $Elimination$

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