## Basic College Mathematics (9th Edition)

Published by Pearson

# Chapters 1-9 - Cumulative Review Exercises: 19

#### Answer

Name of the figure $=$ square Perimeter $= 9$ ft Area $\approx 5.1$ sq ft

#### Work Step by Step

1. Name of the figure Square ($4$ equal sides) 2. Perimeter Let $P =$ perimeter of the square $P = 4 \times 2.25$ (Note that $2.25 = 2\frac{1}{4}$) $P = 9$ ft 3. Area Let $A =$ area of the square $A = 2.25 \times 2.25$ $A = 5.0625$ ft$^{2}$ $A \approx 5.1$ ft$^{2}$

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