## Basic College Mathematics (9th Edition)

$10\frac{4}{15}$
We have $4\frac{3}{5} + 5\frac{2}{3}$ Solving $$(4+5)(\frac{3}{5}+\frac{2}{3})$$ $$9\frac{9+10}{15}$$ $$9\frac{19}{15} = 10\frac{4}{15}$$