Answer
$= (-\frac{1}{3})^{2}+(\frac{1}{4})(-\frac{4}{9}) = 0$
Work Step by Step
$= (-\frac{1}{3})^{2}+(\frac{1}{4})(-\frac{4}{9})$
$= (\frac{1}{9})-(\frac{4}{36})$
$= (\frac{1}{9}) - (\frac{1}{9})$
$=0$
Basic College Mathematics (9th Edition)
by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.
Published by
Pearson
ISBN 10:
0321825535
ISBN 13:
978-0-32182-553-7
Chapter 9 - Basic Algebra - Review Exercises - Page 699: 65
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