Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 673: 80

Answer

$c=-\frac{4}{3}$

Work Step by Step

We are given the equation $\frac{2}{3}-\frac{8}{9}=\frac{c}{6}$. To solve, we must first combine like terms on the left side. $\frac{2}{3}-\frac{8}{9}=\frac{2\times3}{3\times3}-\frac{8}{9}=\frac{6}{9}-\frac{8}{9}=\frac{6-8}{9}=-\frac{2}{9}=\frac{c}{6}$ Multiply both sides by 6. $-\frac{2}{9}\times6=-\frac{12}{9}=-\frac{4}{3}=(\frac{c}{6}\times6)=c$ $c=-\frac{4}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.