## Basic College Mathematics (9th Edition)

$\frac{3}{2}$
$-\frac{8}{5}(-\frac{15}{16})=-\frac{8}{5}\times-\frac{15}{16}=\frac{8\times15}{5\times16}=\frac{120}{80}=\frac{3}{2}$ The signs of both numbers are the same, so the resulting product will be positive.