Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 596: 49


$TF = 90*\sqrt {2} ft$

Work Step by Step

As you see we have a right triangle with two legs $90ft$ and the hypotenuse is the distance from the third base to first base. Then $TF = \sqrt {90^2 + 90^2} = \sqrt {2*90^2} = 90*\sqrt {2} ft$
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