Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.6 Circles - 8.6 Exercises: 29


Difference in the area: 65.94mi$^{2}$

Work Step by Step

We must find the area of each circle and then find the difference in area of the two. Area of a Circle: $A$ = $\pi$$r$$^{2}$ $A$$_{1}$ = (3.14)(5 mi)$^{2}$ $A$$_{1}$ = 78.5 mi$^{2}$ $A$$_{2}$ = (3.14)(2 mi)$^{2}$ $A$$_{2}$ = 12.56 mi$^{2}$ $A$$_{difference}$ = 78.5 mi$^{2}$ - 12.56 mi$^{2}$ $A$$_{difference}$ = 65.94mi$^{2}$
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