Basic College Mathematics (9th Edition)

The change in attendance is $5760-4320=1440$. $\frac{part}{whole}=\frac{percent}{100}$ $\frac{1440}{5760}=\frac{p}{100}$ Cross multiply to solve for p. $5760p=(1440)(100)$ $5760p\div5760=144,000\div5760$ $p=25$