Answer
Answer: Actual Length 21 ft, Actual width 15 ft
Work Step by Step
Let's assume the x is actual length and y is the actual width.
Let's first find length
Now, we will write the proportion for the given details
$\frac{0.5}{6}=\frac{1.75}{x}$
so. $0.5\times x=1.75\times6$ (cross multiply)
$0.5x=10.5$
$x=21$ (divide both sides by 0.5)
Lets find the Width
Now,we will write the proportion for the given details
$\frac{0.5}{6} = \frac{1.25}{x}$
so. $0.5\times x = 1.25\times6$ (cross multiply)
$0.5x = 7.5$
$x = 15$ (divide both sides by 0.5)
i.e. Actual Length 21 ft and actual width 15 ft
