Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Review Exercises - Page 258: 90



Work Step by Step

$\frac{2}{3}=\frac{}{27}$ Now if we get the 27 in the denominator of the first fraction we get the answer. $\frac{2\times9}{3\times9}$ (multiply nominator & denominator by 9) = \frac{18}{27} Answer = 18
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