Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Review Exercises - Page 257: 68

Answer

$1 \frac{25}{64}$

Work Step by Step

$(\frac{1}{4})^{3} + (\frac{5}{8} + \frac{3}{4})$ = $(\frac{1}{4})^{3} + (\frac{5}{8} + \frac{6}{8})$ = $(\frac{1}{4})^{3} + \frac{11}{8}$ = $\frac{1}{64} + \frac{11}{8}$ = $\frac{1}{64} + \frac{88}{64}$ = $\frac{89}{64}$ = $1 \frac{25}{64}$
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