Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 220: 31

Answer

$\frac{19}{45}$.

Work Step by Step

$\frac{8}{9} - \frac{7}{15} = \frac{8 \cdot 5}{9 \cdot 5} - \frac{7 \cdot 3}{15 \cdot 3} = \frac{40}{45} - \frac{21}{45} = \frac{40-21}{45} = \frac{19}{45}$.
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