Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 1 - Whole Numbers - Review Exercises - Page 105: 72

Answer

90,300,000

Work Step by Step

1. Multiply 43 x 21 = 903 a) Multiply 43 x 1 = 43 b) Write a 0 on line below c) Multiply 43 x 2 = 86 (next to 0 so it is 860) d) Add 43 + 860 = 903 2. Count the number of zeroes (5) and add them to the end: 90,300,000
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