Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-8 - Cumulative Review Exercises - Page 622: 29

Answer

There is $ 1\frac{1}{12}$ yd left of the material.

Work Step by Step

Let $x=$ the length of the material left $x = 4.5 - (\frac{5}{3} + \frac{7}{4})$ $x = 4.5 - (\frac{41}{12})$ $x = \frac{13}{12}$ $x = 1\frac{1}{12}$ yd
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