## Basic College Mathematics (10th Edition)

There is $1\frac{1}{12}$ yd left of the material.
Let $x=$ the length of the material left $x = 4.5 - (\frac{5}{3} + \frac{7}{4})$ $x = 4.5 - (\frac{41}{12})$ $x = \frac{13}{12}$ $x = 1\frac{1}{12}$ yd