Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-7 - Cumulative Review Exercises - Page 529: 16

Answer

$x=1\frac{2}{3}$

Work Step by Step

Use cross multiplication to solve for x. $\frac{0.9}{0.75}=\frac{2}{x}$ $0.9x=0.75\times2\ \ \longrightarrow$ Simplify $0.9x=1.5\ \ \longrightarrow$ Divide both sides by 0.9 $\frac{0.9x}{0.9}=\frac{1.5}{0.9}\ \ \longrightarrow$ Simplify using greatest common factor $\frac{0.9x}{0.9}=\frac{1.5\div3}{0.9\div3}\ \ \longrightarrow$ Simplify $x=\frac{0.5}{0.3}\ \ \longrightarrow$ Multiply by 10 to eliminate decimal $x=\frac{0.5\times10}{0.3\times10}\ \ \longrightarrow$ Simplify $x=\frac{5}{3}\ \ \longrightarrow$ Convet to a mixed number $x=1\frac{2}{3}$
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