Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.7 Solving Equations with Several Steps - 9.7 Exercises - Page 678: 55



Work Step by Step

Step 1. Add 2y to both sides of the equation. $-2y+2y+6=6y+2y-10$ $6=8y-10$ Step 2. Add 10 to both sides. $6+10=8y-10+10$ $16=8y$ Step 3. Divide both sides by 8. $\frac{16}{8}=\frac{8y}{8}$ $y=2$
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