Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.7 Solving Equations with Several Steps - 9.7 Exercises - Page 678: 52



Work Step by Step

Step 1. Subtract 2y from both sides of the equation. $5y-2y-5=2y-2y+10$ $3y-5=10$ Step 2. Add 5 to both sides. $3y-5+5=10+5$ $3y=15$ Step 3. Divide both sides by 3. $\frac{3y}{3}=\frac{15}{3}$ $y=5$
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