Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.7 Solving Equations with Several Steps - 9.7 Exercises - Page 676: 13



Work Step by Step

We are given the equation $-\frac{1}{2}z+2=-1$. In order to solve, we can first subtract 2 from both sides. $-\frac{1}{2}z+2-2=-1-2$ $-\frac{1}{2}z=-3$ Multiply both sides by -2. $(-\frac{1}{2}z\times-2)=z=-3\times-2=6$ $z=6$
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