Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.7 Solving Equations with Several Steps - 9.7 Exercises - Page 676: 12



Work Step by Step

We are given the equation $-12a-3=21$. In order to solve, we can first add 3 to both sides. $-12a-3+3=21+3$ $-12a=24$ Divide both sides by -12. $\frac{-12a}{-12}=\frac{24}{-12}$ $a=-2$
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