Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 668: 6



Work Step by Step

We can plug in $r=-2$ to the equation to see if it is a solution. $6r-3=6(-2)-3=6\times-2-3=-12-3=-15\ne-14$ Therefore, $r=-2$ is not a solution to the given equation.
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