Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 668: 5

Answer

No.

Work Step by Step

We can plug in $z=-8$ to the equation to see if it is a solution. $2z-1=2(-8)-1=2\times-8-1=-16-1=-17\ne-15$ Therefore, $z=-8$ is not a solution to the given equation.
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