Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - 9.4 Order of Operations - 9.4 Exercises - Page 654: 41

Answer

$12$

Work Step by Step

$\frac{-2(4^2) - 4(6-2)}{-4(8-13)\div(-5)} = \frac{-2(16) - 4(4)}{-4(-5)\div(-5)} = \frac{-48}{-4} = 12$
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