Basic College Mathematics (10th Edition)

$5(4^{2})-6(1+4)-(-3)$ 1. Solve inside the parenthesis first, so: $5(16) -6(5)-(-3)$ 2. When 2 negatives multiply, they become positive: $5(16) -6(5)+3$ 3. Expand the parenthesis: $80 -30+3 = 53$