Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - 9.1 Signed Numbers - 9.1 Exercises - Page 628: 17

Answer

$0\gt-2$

Work Step by Step

$0\gt-2$ This is because 0 is to the right of -2 on the number line. Therefore, 0 has a value that is greater than -2.
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