Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 8 - Geometry - Mixed Review Exercises - Page 618: 29

Answer

$x \approx 12.6$ km

Work Step by Step

1. Use the Pythagorean Theorem to solve for $x$ $a^{2} + b^{2} = c^{2}$ $x^{2} + 6^{2} = 14^{2}$ $x^{2} + 36 = 196$ $x^{2} = 160$ $x = \sqrt 160$ $x = 12.649...$ km $x \approx 12.6$ km
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