Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - Mixed Review Exercises - Page 617: 22


$Perimeter=282~cm$ $Area=4190~cm^2$

Work Step by Step

First, we find the perimeter. We simply add up the lengths of all of the given outer sides: $Perimeter=72+19+50+19+72+50=282~cm$ To find the area we break up the figure into two pieces: - Left parallelogram (72 cm x 45 cm) - Right rectangle (50 cm x 19 cm) And add up the two areas. Left parallelogram: We know that the area of a parallelogram is given by: $Area=base*height$ $A=bh$ So we have: $A=72*45$ $A=3240~cm^2$ Right rectangle: We know that the area of a rectangle is given by: $Area=length*width$ $A=lw$ So we have: $A=19*50$ $A=950~cm^2$ Now we add up the two areas: $Total~area=3240+950=4190~cm^2$
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