Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - Mixed Review Exercises - Page 616: 8


Parallelogram. $Area=288~mm^2$ $Perimeter=78$ mm

Work Step by Step

The figure is a parallelogram. We know that the area of a parallelogram is given by: $Area=base*height$ $A=bh$ So we have: $A=24*12$ $A=288~mm^2$ To find the perimeter, we simply add up the side lengths: $Perimeter=24+15+24+15$ $Perimeter=48+30$ $Perimeter=78$ mm
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