## Basic College Mathematics (10th Edition)

Published by Pearson

# Chapter 8 - Geometry - 8.9 Similar Triangles - 8.9 Exercises - Page 600: 14

#### Answer

$a = 2$ ft $b = 6$ ft

#### Work Step by Step

1. Solve for $a$ $\frac{a}{6} = \frac{3}{9}$ $a = \frac{3 \times 6}{9}$ $a = \frac{18}{9}$ $a = 2$ ft 2. Solve for $b$ $\frac{b}{2} = \frac{9}{3}$ $b = \frac{9 \times 2}{3}$ $b = \frac{18}{3}$ $b = 6$ ft

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