Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.7 Volume - 8.7 Exercises - Page 586: 22


$V\approx 4.186\approx 4.2~in^3$

Work Step by Step

We know that the volume of a cone (radius $r$, height $h$) is given by: $\displaystyle V=\frac{1}{3}\pi r^2 h$ We plug in our values ($r=diameter/2=2/2=1~in$, $h=4~in$) to find the volume: $\displaystyle V=\frac{1}{3}\pi 1^2 4$ $\displaystyle V=\frac{4\pi}{3}$ $V\approx 4.186\approx 4.2~in^3$
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