Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 566: 28


Total area of nylon needed: 23.50 ft$^{2}$

Work Step by Step

To find out how much fabric is needed we must add the areas of all the triangles together. $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$$_{total}$ = ($\frac{1}{2}$(3 ft)(3.5 ft)) +($\frac{1}{2}$(3 ft)(3.5 ft)) + ($\frac{1}{2}$(4 ft)(6.5 ft)) $A$$_{total}$ = 5.25 ft$^{2}$ + 5.25 ft$^{2}$ + 13 ft$^{2}$ $A$$_{total}$ = 23.50 ft$^{2}$
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