Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 565: 14


Area of the shaded part = 54 ft$^{2}$

Work Step by Step

To find the area of the shaded portion we simply find the area of the entire triangle and subtract the area of the un-shaded square. Area of a Square: $A$$_{sqr}$ = $s$$^{2}$ Therefore: $A$$_{sqr}$ = (3 ft)$^{2}$ $A$$_{sqr}$ = 9 ft$^{2}$ Area of a Triangle: $A$$_{tri}$ = $\frac{1}{2}$$b$$h$ Therefore: $A$$_{tri}$ = $\frac{1}{2}$(18 ft)(7 ft) $A$$_{tri}$ = 63 ft$^{2}$ $A$$_{total}$ = $A$$_{tri}$ - $A$$_{sqr}$ Therefore: $A$$_{total}$ = 63 ft$^{2}$ - 9 ft$^{2}$ = 54 ft$^{2}$
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