Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 551: 19


The perimeter of the square mat is $48$ $m$ The area of the square mat is $144$ $m^{2}$

Work Step by Step

Step 1: Find the perimeter. Let $ P = $ perimeter of square mat $P = 4(12)$ (square has four equal sides, each side is $12$m) $P = 48$m Step 2: Find the area. Let $ A = $ area of square mat $A = 12^{2}$ $A = 144 m^{2}$ Refer to Attachment1 below.
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