## Basic College Mathematics (10th Edition)

$74^\circ\ F=23.3^\circ\ C$
$C=\frac{5(F-32)}{9}$ Substitute 74 for F and solve for C. $C=\frac{5(74-32)}{9}=\frac{5(42)}{9}=\frac{210}{9}=23.3\overline3$