Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 7 - Measurement - Test - Page 528: 31

Answer

$74^\circ\ F=23.3^\circ\ C$

Work Step by Step

$C=\frac{5(F-32)}{9}$ Substitute 74 for F and solve for C. $C=\frac{5(74-32)}{9}=\frac{5(42)}{9}=\frac{210}{9}=23.3\overline3$
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