## Basic College Mathematics (10th Edition)

(a) Use the formula to convert 5C. $F=\frac{9\times C}{5}+32$ $\frac{9\times5}{5}+32=\frac{45}{5}+32=9+32=41F$ (b) 0C is 32F. Use the formula to convert 15C. $F=\frac{9\times C}{5}+32$ $\frac{9\times15}{5}+32=\frac{135}{5}+32=27+32=59F$