## Basic College Mathematics (10th Edition)

Published by Pearson

# Chapter 5 - Ratio and Proportion - 5.4 Solving Problems - 5.4 Exercises - Page 357: 30

#### Answer

1. It is wrong because $\frac{24}{32}$ is not equal to $\frac{24}{30}$ 2. $\frac{12}{16},\frac{18}{24}, \frac{24}{32}, \frac{30}{40}$

#### Work Step by Step

1. In order to prove that this is not true, we must make the numerator or the denominator the same the the example's; ie $\frac{6}{8} = \frac{6\times4}{8\times4} = \frac{24}{32}$ This proves it wrong because $\frac{24}{32}$ is not equal to $\frac{24}{30}$ 2. To create a true proportion of this fraction, you need to multiply the top and bottom by the same number, eg $\frac{6}{8} = \frac{2\times6}{2\times8} = \frac{12}{16}$ $\frac{6}{8} = \frac{3\times6}{3\times8} = \frac{18}{24}$ $\frac{6}{8} = \frac{4\times6}{4\times8} = \frac{24}{32}$ $\frac{6}{8} = \frac{5\times6}{5\times8} = \frac{30}{40}$

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