Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 4 - Decimals - Review Exercises - Page 323: 54

Answer

= $10\frac{3}{20}$ or 10.15

Work Step by Step

11-3.06$\div$(3.95-0.35) = 11-3.06$\div$(3.6) (first solve bracket) = 11 - ($\frac{3.06}{3.60}$) = 11 - ($\frac{17}{20}$) = $\frac{11\times20}{1\times20}-\frac{17}{20}$ (LCM of 1 & 20 is 20) = $\frac{220}{20}-\frac{17}{20}$ = $\frac{220-17}{20}$ = $\frac{203}{20}$ = $10\frac{3}{20}$ or 10.15
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