## Basic College Mathematics (10th Edition)

= $10\frac{3}{20}$ or 10.15
11-3.06$\div$(3.95-0.35) = 11-3.06$\div$(3.6) (first solve bracket) = 11 - ($\frac{3.06}{3.60}$) = 11 - ($\frac{17}{20}$) = $\frac{11\times20}{1\times20}-\frac{17}{20}$ (LCM of 1 & 20 is 20) = $\frac{220}{20}-\frac{17}{20}$ = $\frac{220-17}{20}$ = $\frac{203}{20}$ = $10\frac{3}{20}$ or 10.15