Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Test - Page 259: 9

Answer

$\frac{23}{36}$

Work Step by Step

$\frac{2}{9}+\frac{5}{12}=\frac{2\times4}{9\times4}+\frac{5\times3}{12\times3}=\frac{8}{36}+\frac{15}{36}=\frac{8+15}{36}=\frac{23}{36}$
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