Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - Summary Exercises - Operations with Fractions - Page 236: 43

Answer

$\frac{15}{45}$

Work Step by Step

In order to rewrite $\frac{3}{9}$ with a denominator of 45, we must multiply both the numerator and the denominator of the original fraction by 5. $\frac{3}{9}=\frac{3\times5}{9\times5}=\frac{15}{45}$
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