Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - Summary Exercises - Operations with Fractions - Page 235: 20

Answer

$\frac{2}{15}$

Work Step by Step

$\frac{4}{5}-\frac{2}{3}=\frac{4\times3}{5\times3}-\frac{2\times5}{3\times5}=\frac{12}{15}-\frac{10}{15}=\frac{12-10}{15}=\frac{2}{15}$
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