Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 220: 23

Answer

$ \frac{1}{2}$.

Work Step by Step

$\frac{5}{6} - \frac{1}{3} = \frac{5}{6} - \frac{1 \cdot 2}{3 \cdot 2} = \frac{5}{6} - \frac{2}{6} = \frac{5 - 2}{6} = \frac{3}{6} = \frac{1}{2}$.
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