## Basic College Mathematics (10th Edition)

$\frac{3}{4} = \frac{48}{64}$
$\frac{3}{4} and \frac{48}{64}$ Now Lets first write $\frac{48}{64}$ as the prime factorization of both numerator and denominator. $\frac{2\times2\times2\times2\times3}{2\times2\times2\times2\times2\times2}$ Now, we divide the numerator and denominator by any common factors and replace the divided factor with 1. $\frac{1\times1\times1\times1\times3}{1\times1\times1\times1\times2\times2}$ =$\frac{3}{2\times2}$ = $\frac{3}{4}$ i.e. $\frac{3}{4} = \frac{48}{64}$