Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 2 - Multiplying and Dividing Fractions - Mixed Review Exercises - Page 192: 21

Answer

$\frac{49}{32}in^{2}$

Work Step by Step

Area = Length $\times$ width = $1\frac{3}{4}in \times \frac{7}{8}in$ = $\frac{7}{4} \times \frac{7}{8}in^{2}$ = $\frac{7\times7}{4\times8}in^{2}$ (multiply nominator and denominator) = $\frac{49}{32}in^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.