Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 2 - Multiplying and Dividing Fractions - 2.5 Multiplying Fractions - 2.5 Exercises - Page 148: 19

Answer

$\frac{39}{42} \cdot \frac{7}{13} \cdot \frac{7}{24} = \frac{7}{48}$.

Work Step by Step

$\frac{39}{42} \cdot \frac{7}{13} \cdot \frac{7}{24} = \frac{39}{6} \cdot \frac{1}{13} \cdot \frac{7}{24} = \frac{3}{6} \cdot \frac{1}{1} \cdot \frac{7}{24} = \frac{1}{6} \cdot \frac{1}{1} \cdot \frac{7}{8} = \frac{1 \cdot 1 \cdot 7}{6 \cdot 1 \cdot 8} = \frac{7}{48}$.
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