Answer
The point $(1\frac{1}{2},-3)$ lies in $\text{Quadrant IV.}$
Work Step by Step
$\text{Quadrant IV}$ is the quadrant in the lower right corner of the coordinate plane. Any point that has a positive $x$ coordinate and a negative $y$ coordinate will be in this quadrant, because these coordinates place the point both below and to the right of the origin.
