Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Skills Handbook - Squaring Numbers and Finding Square Roots - Exercises - Page 889: 15


$y=1\text{ or }y=-1$

Work Step by Step

We start with the given equation: $y^2+7=8$ In order to get the term with $y$ by itself, we subtract $7$ from both sides of the equation: $$y^2+7-7=8-7$$$$y^2=1$$To solve the equation $y^2=1$, we must perform the opposite operation of squaring, which is taking the square root, in order to clear the exponent: $$y^2=1$$$$\sqrt {y^2}=\sqrt {1}$$$$y=\pm1$$$$y=1\text{ or }y=-1$$
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