Geometry: Common Core (15th Edition)

G) $10.9\ in^2$
The area of a triangle is $\frac{1}{2}bh$. For a right triangle, the lengths of the legs are the base and the height. $\frac{1}{2}bh=\frac{1}{2}(2.2)(9.9)=(1.1)(9.9)=10.89\approx10.9$