Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - Get Ready! - Page 487: 10

Answer

$x = 2 \sqrt {13}$

Work Step by Step

We know that each leg of the triangle is the geometric mean of the hypotenuse and the hypotenuse that is adjacent to that leg: $\frac{a}{y} = \frac{y}{b}$, where $a$ and $b$ are the length of the hypotenuse and the length of the segment of the hypotenuse closest to the leg, and $y$ is the length of the leg. $\frac{9 + 4}{x} = \frac{x}{4}$ Evaluate what is in brackets first: $\frac{13}{x} = \frac{x}{4}$ Use the cross products property to get rid of the fractions: $x^2 = 52$ Rewrite $52$ as the product of a perfect square and another factor: $x^2 = 4 • 13$ Take the positive square root to solve for $x$: $x = 2 \sqrt {13}$
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