Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - Chapter Review - Page 536: 13


sin $A$ = $\frac{2\sqrt {19}}{20}$ or $\frac{\sqrt {19}}{10}$ cos $A$ = $\frac{18}{20}$ or $\frac{9}{10}$ tan $A$ = $\frac{2\sqrt {19}}{18}$ or $\frac{\sqrt {19}}{9}$

Work Step by Step

The trigonometric ratios we want to find are given below: sin $A$ = $\frac{opposite}{hypotenuse}$ cos $A$ = $\frac{adjacent}{hypotenuse}$ tan $A$ = $\frac{opposite}{adjacent}$ Let's plug in values given for each of the sides: sin $A$ = $\frac{2\sqrt {19}}{20}$ or $\frac{\sqrt {19}}{10}$ cos $A$ = $\frac{18}{20}$ or $\frac{9}{10}$ tan $A$ = $\frac{2\sqrt {19}}{18}$ or $\frac{\sqrt {19}}{9}$
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