Geometry: Common Core (15th Edition)

sin $A$ = $\frac{2\sqrt {19}}{20}$ or $\frac{\sqrt {19}}{10}$ cos $A$ = $\frac{18}{20}$ or $\frac{9}{10}$ tan $A$ = $\frac{2\sqrt {19}}{18}$ or $\frac{\sqrt {19}}{9}$
The trigonometric ratios we want to find are given below: sin $A$ = $\frac{opposite}{hypotenuse}$ cos $A$ = $\frac{adjacent}{hypotenuse}$ tan $A$ = $\frac{opposite}{adjacent}$ Let's plug in values given for each of the sides: sin $A$ = $\frac{2\sqrt {19}}{20}$ or $\frac{\sqrt {19}}{10}$ cos $A$ = $\frac{18}{20}$ or $\frac{9}{10}$ tan $A$ = $\frac{2\sqrt {19}}{18}$ or $\frac{\sqrt {19}}{9}$